The “a” number needs to have the factors found in the set of numbers 2, 3, 4, and 5, as squaring or cubing numbers won’t change their factors. The “a” is therefore solved by 2*3*5, or 30, as 4 is just 2*2 (which would get covered in the “b” number to come). The “b” is 3*4*5, or 60, as 30^4 satisfies 30^2.