spaceStationSpaz
spacestationspaz
spaceStationSpaz

In an argument on Facebook that was completely unrelated to tinder and actually politically motivated I had my opponent resort to calling me ugly. He did so after only a few exchanges, so clearly this was the place he intended to take the argument the whole time. It was a very satisfying exchange for two reasons.

iirc correctly removing the door on my '93 to replace the lock actuator was a PITA and had to be done by a shop. The driver door wouldn't open and for months I had to get in and out through the passenger side. I don't think its as easy as all that, check the lexus forums.

I think it's time to either retire or rephrase the introvert/extrovert question, everyone gives the same answer and it is clear that this is not really a binary distinction as we once understood it to be.

I think I figured it out, i didn't include drag deceleration in vy, which makes it start falling much sooner. Then vx could still be important.

*terminal velocity was only added to the falling velocity calculation, I did the parabolic maxima with vtotal(sin(20))

I did the calculation using standard ballistic trajectory equations for an AR-15, 831m/s and 250m/s drag deceleration (I found a reference, with measured and calculated extremely close). Assuming 90m/s terminal velocity, the bullet would still reach a height of 200m with an angle as low as 20 degrees from horizontal,

OK, even for an angle of 20 degrees from horizontal, (AR-15, 831 m/s, 250m/s deceleration due to drag) the bullet would still reach a height of 200 m before falling, and that would take 25 seconds. By then the horizontal velocity would be zero due to drag. So the entire velocity would still be just the terminal

*60 degrees from horizontal.

My rough calculations: assume an AR-15 with muzzle velocity 831m/s and following the drag deceleration curve I posted elsewhere in this post, -300m/s. Also assume terminal falling velocity of 76m/s. Fired at 60 degrees from vertical and ignoring other deceleration forces (tumbling et al), the speed would fall to

Doing trig on the phone is hard. Square root of the sum of the squares: v=√(vx^2+vy^2). Now all I want to do at work tomorrow is write a mathematica script to calculate killing angles of bullets.

drag deceleration of a bullet

for an angle greater than 75 degrees, less than 25% of the initial velocity is in the horizontal direction, and 17% at 80 degrees. Higher than that it falls off rapidly. So most of the final speed will be in the form of terminal Y velocity, also a much smaller effective region of impact (since you'd basically have to

dammit, I forgot my unit circle. At 45 cos=sin=√2/2~.707, so 70%. Cos 60=1/2 so higher than 60%

"ballistic trajectory" doesn't imply lethality. It simply refers to the method of calculating the vector (x and y direction) quantities.

strike that, reverse it. Cos or sin, respectively.

the horizontal and vertical speed are vector quantities. Though the are not independent of each other they can be calculated independently based on the angle and initial velocity. The component velocities (x and y, to save space) are equal to the initial velocity times the sine or cosine of the angle, respectively.

Doesn't aftermarket decrease the value vs stock? Or at least depreciate faster?

I drove some beast of an American luxury car a few months back (Chrysler 300, I think) and it had a ton of bullshit options, like cup holders that can chill OR heat your beverage. But man, the in dash navigation was nice. The GUI was about as hamfisted as you'd expect, they'd be much better off going with something

Your strongest point, imo, is the comparison to the London system.

I'm tired of being pending.