You may also notice that the displacement also scales on the square of the bore. So for a constant displacement, torque remains the same regardless of bore/stroke ratio.

I think you missed a stage right before #4:

Not even with much larger bearings and conrod cross-section area?

Torque is a pointless number. If you have a motor that gives one million newton meters at 1 rpm it will not perform in any way different from a motor that gives 100 Nm at 10000 rpm. Give or take whatever polar inertia differs.

You’re right. It would be 28.6 m/s which is more than the largest number I have ever seen at 26 m/s. I made the mistake to trust the wrong calc tool.

“Peak” means only just that. It does not imply that there is nothing below.

A 2020 Honda CBR1000RR delivers 114 Nm. At 11000 rpm...

The peaky register of a liter bike has more to do with cam timing than bore/strike ratio.

Is this related to gun-toting, freedom-loving sovereign citizens just itching for a reason to protect their property with lethal violence?

Stone me if you want, but that is a gorgeous car.

I released a bottle full with NOx in my Taycan and it didn’t go any faster. What a drag!

Contemporary 1-liter bikes deliver over 200 HP at like 14k rpm these days.

Most likely precisely the case.

My 2009 Merc E280 consumes marginally less my 1994 Buick Park Avenue Ultra. Both have V6:es, the Buick 225 HP pushrod and 4-step auto, Merc 233 HP VVT/DOHC and 7-step auto, and is is slightly lighter. All things considered, they are equals in performance and mileage despite about 15 years of development.

It is kind of odd, because my 1986 Camaro with a carburetor got about 27 mpg highway.

What kind of weird euphemism is “ordnance”, really?

Just run on ethanol and thumb your nose at Greta Thunberg.

You mean there will finally be a sedan with a big burly pushrod V8? WHEEEE!

Thank you, that is correct!

Where I live and work as a consultant it is the other way around. If you have a nice car there will be grumbles about being paid too much.